WebEasy Solution Verified by Toppr Correct option is A) As we know each term is G.P. is geometric mean of the terms equidistant from it. Here (m+n) m and (mn) m terms are equidistant So therefore m m term will be G.M. of (m+n) m and (mn) mi.e. mn= 9×4=6 Was this answer helpful? 0 0 Similar questions WebTo find the n th term of a GP, we require the first term and the common ratio. If the common ratio is not known, the common ratio is calculated by finding the ratio of any term to its …
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WebMar 29, 2024 · Transcript. Example 4, In an A.P. if mth term is n and the nth term is m, where m n, find the pth term. We know that an = a + (n 1) d i.e. nth term = a + (n 1) d Thus, mth term = am = a + (m 1) d It is given that mth term is n a + (m 1) d = n Also, it is given that nth term is m a + (n 1) d = m First we find common difference, Subtracting (2) from (1) [a + (m 1) d] … WebThe nth term of a GP is an =128 a n = 128. The first term of the GP is a = 2 a = 2. The common ratio of the GP is r =2 r = 2. Now use the condition if the first and nth term of a …
WebMay 28, 2024 · Given Mth and Nth term of a Geometric progression. Find its Pth term. Examples: Input: m = 10, n = 5, mth = 2560, nth = 80, p = 30 Output: pth = 81920 Input: m = 8, n = 2, mth = 1250, nth = 960, p = 15 Output: 24964.4 Approach: Let a is the first term and r is the common ratio of the given Geometric Progression. Therefore WebThe geometric sequence is sometimes called the geometric progression or GP, for short. For example, the sequence 1, 3, 9, 27, 81 is a geometric sequence. Note that after the first …
WebThe (m + n)th and the (m - n)th terms of a GP are p and q respectively. Show that the mth and the nth terms of the GP are √pq and (q p)(m 2n) Solution Let a be the first term and r … WebIn G.P. (p+q) th term is m, (p−q) th term is n, then p th term is A nm B nm C nm D nm Medium Solution Verified by Toppr Correct option is B) Let the first term of G.P be 'a' and common ratio be 'r' given T p+q=ar p+q−1=m T p−q=ar p−q−1=n then multiplying the above two equations : mn=a 2r 2p−2=(ar p−1) 2 ⇒ar p−1= mn
WebJul 5, 2024 · In an A.P. S n = 3n 2 + 5n and T m = 164, then m equals to : (a) 26 (b) 27 (c) 28 (d) None of these. Answer: (b) 27 Question 11. A.M. of two number is 10 and GM. is 8, the numbers are (a) a = 4, b = 16 (b) a = 2, b = 8 (c) a = 4, b = 9 (d) a = 2, b = 18. Answer: (a) a = 4, b = 16 Question 12.
WebJun 4, 2024 · Plus One Maths Sequences and Series 4 Marks Important Questions. Question 1. Given sum of three consecutive terms in an AP is 21 and their product is 280 (IMP-2011) i) Find the middle term of the above terms. ii) Find the remaining two terms of the above AP. Answer: i) Let the three consecutive terms be. a-d, a, a + d. a-d + a + a + d = 21. flight 1942 streaming itaWebMar 16, 2024 · Find Pth term of a GP if Mth and Nth terms are given in C - In this problem we are given five values m, n, mth term, nth term, p. Our task is to Find Pth term of a GP if … flight 1942 southwestWebDec 4, 2024 · If the (m+n)th term of a gp is p and (m-n)th terma is q, show that mth term and nth term are √pq and p (q/p)^m/2n See answers Advertisement kvnmurty Let the given … chem hoodWebThe general form of an Arithmetic Progression is a, a + d, a + 2d, a + 3d and so on. Thus nth term of an AP series is T n = a + (n - 1) d, where T n = n th term and a = first term. Here d = common difference = T n - T n-1. Sum of … chemhr upmc.eduWebNov 1, 2024 · Expanding and cancelling terms we get $\frac{2an}{d} + n^2 = \frac{a(m+r)}{d} + mr$. Transposing terms, we have $\frac{a}{d}(2n-m-r) = mr-n^2$. Consequently, $\frac ad = \frac{mr - n^2}{2n-m-r}$. Since we know the answer is $\frac{-n}{2}$, let us rewrite the above as $\frac{-n}{2} \times \frac{2mr - 2n^2}{n(m+r) - 2n^2}$, where we multiplied ... flight 1943 from phoenixWebSep 7, 2024 · Let the first term of AP be m and common difference as d. Let the GP first term as l and common ratio as s. The n th term of an AP is given as t n = a + (n – 1)d where a is the first term and d is the common difference. The n th term of a GP is given by t n = ar n-1 where a is the first term and r is the common ratio. The p th term (t p) of both AP and … flight 1942 مترجمWebThe mth term of a Geometrical Progression is n and nth term is m. Find (m+n)th term. I've tried this: T m = ar m-1 = n (Eq 1) T n = ar n-1 = m (Eq 2) Subracting 2 from 1 r m - r - r n + r = n-m r m - r n = n-m r m + m = r n + n I don't know how to proceed. I don't even know if I have done this correctly until this point. sequences-and-series flight 1943 southwest